21c^2-52c+7=

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Solution for 21c^2-52c+7= equation:


Simplifying
21c2 + -52c + 7 = 0

Reorder the terms:
7 + -52c + 21c2 = 0

Solving
7 + -52c + 21c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(1 + -7c)(7 + -3c) = 0

Subproblem 1

Set the factor '(1 + -7c)' equal to zero and attempt to solve: Simplifying 1 + -7c = 0 Solving 1 + -7c = 0 Move all terms containing c to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -7c = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -7c = 0 + -1 -7c = 0 + -1 Combine like terms: 0 + -1 = -1 -7c = -1 Divide each side by '-7'. c = 0.1428571429 Simplifying c = 0.1428571429

Subproblem 2

Set the factor '(7 + -3c)' equal to zero and attempt to solve: Simplifying 7 + -3c = 0 Solving 7 + -3c = 0 Move all terms containing c to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + -3c = 0 + -7 Combine like terms: 7 + -7 = 0 0 + -3c = 0 + -7 -3c = 0 + -7 Combine like terms: 0 + -7 = -7 -3c = -7 Divide each side by '-3'. c = 2.333333333 Simplifying c = 2.333333333

Solution

c = {0.1428571429, 2.333333333}

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